Question 1: The sides of a right-angled triangle containing the right angle are and
. if the area of the triangle is
calculate the lengths of its sides.
Answer:
Therefore the sides are 12 cm, 5 cm and 13 cm.
Question 2: The hypotenuse of a right-angled triangle is 26 cm and the sum of other two sides is 34 cm. find the lengths of its sides.
Answer:
Let one side be
Therefore the other side would be
Using Pythagoras theorem
Therefore the sides are 10 cm and 24 cm.
Question 3: The sides of a right-angled triangle are . Find: The value of
, The lengths of its sides, and Its area.
Answer:
Using Pythagoras theorem
Therefore the length of the sides are 7 cm, 21 cm and 25 cm.
Question 4: The hypotenuse of a right-angled triangle exceeds one side by 1 cm and the other side by 18 cm; find the lengths of the sides of the triangle.
Answer:
Let the hypotenuse
The other two sides would then be
Using Pythagoras theorem
Therefore the sides are 25 cm, 24 cm and 7 cm.
Question 5: The diagonal of a rectangle is 60 m more than its shorter side and the larger side is 30 m more than the shorter side. Find the sides of the rectangle.
Answer:
Let the shorter side
Diagonal
Larger sides
Using Pythagoras theorem
Therefore the sides are 90 cm, 150 cm and 120 cm.
Question 6: The perimeter of a rectangle is 104 m and its area is 640 m². Find its length and breadth.
Answer:
Let the length
Let the width
Therefore
Substituting in i)
Therefore
Hence the sides are 32 cm and 20 cm.
Question 7: A footpath of uniform width runs around the inside of a rectangular field 32 m long and 24 m wide. If the path occupies 208 m², find the width of the footpath.
Answer:
Let the width of the footpath
Area of the rectangular field
Area of the rectangular field not covered by the footpath
Therefore
Therefore the width of the footpath = 2 m
Question 8: Two squares have sides . the sum of their areas is 656 sq.cm. express this as an algebraic equation in x and solve the equation to find the sides of the squares.
Answer:
The sides of the square are 16 cm and 20 cm.
Question 9: The dimensions of a rectangular field are 50 m by 40 m. a flower bed is prepared inside this field leaving a gravel path of uniform width all around the flower bed and graveling the path at Rs. 30 and Rs. 20 per square meter, respectively, is Rs. 52,000. Find the width of the gravel path.
Answer:
Let the width of the gravel path
Area of the flower bed
Are of the gravel path
Total cost of work
Therefore the width of the gravel path
Question 10: An area is paved with square tiles of a certain size and the number required is 128. If the tiles had been 2 cm smaller each way, 200 tiles would have been needed to pave the same area. Find the size of the larger tiles.
Answer:
Let the width of the larger tile
Width of the smaller tile
Thereofore
Therefore the width of the large tile = 10 cm
Question 11: A farmer has 70 m of fencing, with which he encloses three sides of a rectangular sheep pen; the fourth side being a wall. If the area of the pen is 600 sq.m. find the length of its shorter side.
Answer:
Let the shorter side
Therefore the larger side
Therefore
Therefore the larger side = 30 m (when shorter side is 20 m) or 40 m (when shorter side is 15 m)
Question 12: A square lawn is bounded on three sides by a path 4 m wide. If the area of the path is 7/8 that of the lawn, find the dimensions of the lawn.
Answer:
Let the width of the path
Therefore the width of the square
Question 13: The area of a big rectangular room is 300 m². If the length were decreased by 5 m and the breadth increased by 5 m; the area would be unaltered. Find the length of the room.
Answer:
Let the length of the room
Let the breadth of the room
Also