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OR

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Question 14: Evaluate without using trigonometric tables:

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Question 16: Without using trigonometric tables, evaluate

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Question 17: Prove the identity:

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Question 18: If , show that

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Therefore LHS = RHS. Hence proved.

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Question 24: Without using trigonometric tables evaluate :

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Given:

Question 25: Without using trigonometric tables evaluate :

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Given:

The qustion no.2

Incorrect..

Thank you for pointing out. It was a typing mistake. I have corrected it.

It’s unable to understand the solution of question no.7

There was a typing mistake in the question… i have added one more line of explanation…. it should be easy to understand now.

I fixed it. Thank you for your contribution.

Technical issues from Q 12

Please sort them out

Let me check

I fixed it. Thank you for your contribution.

Very helpful.

ques 9 has

wrong answer

Good catch… it was a typo. We have corrected it.

(1-tanA)² + (1+tanA)² = 2sec²A

LHS = (1-tanA)² + (1+tanA)²

LHS = 1-2tanA+tan²A+1+2tanA+tan²A

LHS = 2 + 2tan²A

LHS = 2(1+tan²A)

Here, we use formula (1+tan²A)=sec²A

LHS = 2sec²A=RHS

By : MANGESH K REPAL

Sir, there are multiple ways of solving a problem. I have also included your way of solving the problem. Thanks