Perimeter and Area of Plane Figures

Triangle

Let a, b, c denotes the sides of the Triangle. Then:

\displaystyle \text{Perimeter } = a + b + c

\displaystyle \text{Semi-Perimeter }(s) = \frac{1}{2}  (a + b + c)

\displaystyle \text{Area } = \sqrt{s(s-a)(s-b)(s-c)}

\displaystyle \text{Area } = \frac{1}{2} \times Base \times Height = \frac{1}{2} bh

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Right-angled Triangle

Let b be the base, h be the height (or perpendicular) and a be the Hypotenuse. Then,

\displaystyle \text{Perimeter } = a + b + h

\displaystyle \text{Area } = \frac{1}{2} \times Base \times Height = \frac{1}{2} bh

\displaystyle \text{Hypotenuse }= \sqrt{b^2 + h^2}

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Isosceles Right – angled triangle

Let the equal sides be a .

\displaystyle \text{Hypotenuse }= \sqrt{a^2+a^2} = \sqrt{2} a

\displaystyle \text{Perimeter } = 2a + \sqrt{2}a

\displaystyle \text{Area } = \frac{1}{2} \times Base \times Height = \frac{1}{2} a^2

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Equilateral Triangle

Let each of the side is a . Then

\displaystyle \text{Perimeter } = 3a

\displaystyle \text{Height }= \frac{\sqrt{3}}{2}  a

\displaystyle \text{Area } = \frac{1}{2} \times Base \times Height = \frac{1}{2} a \times \frac{\sqrt{3}}{2}  a = \frac{\sqrt{3}}{4}  a^2

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Isosceles Triangle

Let the equal sides be a . Let the base be 2b . Then

\displaystyle \text{Perimeter } = 2a+ 2b

\displaystyle \text{Height }= \sqrt{a^2 - b^2}

\displaystyle \text{Area } =  \frac{1}{2}  \times 2b \times \sqrt{a^2 - b^2} = b \sqrt{a^2 - b^2}

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Rectangle

Let the length = l and breadth = b . Then

\displaystyle \text{Perimeter } = 2 (l+b)

\displaystyle \text{Area } = lb

\displaystyle \text{Diagonal }= \sqrt{l^2 + b^2}

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Square

Let the side of the square = a . Then

\displaystyle \text{Perimeter } = 4a

\displaystyle \text{Area } = a^2

\displaystyle \text{Diagonal }= \sqrt{2} a

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Parallelogram

Let the two adjacent sides of the parallelogram be a and b

\displaystyle \text{Perimeter } = 2 (a+b)

\displaystyle \text{Area } = Base \times Height

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Rhombus

A parallelogram that has all the sides equal is called a rhombus. If d_1 and d_2 are the diagonals, then

\displaystyle \text{Side }=  \frac{1}{2}  \sqrt{{d_1}^2 + {d_2}^2}

\displaystyle \text{Perimeter } = 4 \times Side = 2\sqrt{{d_1}^2 + {d_2}^2}

\displaystyle \text{Area } =  \frac{1}{2}  d_1 d_2

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Trapezium

A trapezium is a quadrilateral two of whose sides are parallel. A trapezium whose non-parallel sides are equal is known as an isosceles trapezium.

Let a and b be the parallel sides and h be the distance between the parallel sides. Then

\displaystyle \text{Area } =  \frac{1}{2}  (a+b) \times h

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Quadrilateral

If h_1 and h_2 are the perpendicular distances from the diagonal AC of the quadrilateral ABCD from the vertices B and D respectively. Then,

\displaystyle \text{Area } =  \frac{1}{2}  (AC)(h_1 + h_2)

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