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OR
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Question 14: Evaluate without using trigonometric tables:
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Question 16: Without using trigonometric tables, evaluate
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Question 17: Prove the identity:
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Question 18: If , show that
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Therefore LHS = RHS. Hence proved.
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Question 24: Without using trigonometric tables evaluate :
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Question 25: Without using trigonometric tables evaluate :
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The qustion no.2
Incorrect..
Thank you for pointing out. It was a typing mistake. I have corrected it.
It’s unable to understand the solution of question no.7
There was a typing mistake in the question… i have added one more line of explanation…. it should be easy to understand now.
I fixed it. Thank you for your contribution.
Technical issues from Q 12
Please sort them out
Let me check
I fixed it. Thank you for your contribution.
Very helpful.
ques 9 has
wrong answer
Good catch… it was a typo. We have corrected it.
(1-tanA)² + (1+tanA)² = 2sec²A
LHS = (1-tanA)² + (1+tanA)²
LHS = 1-2tanA+tan²A+1+2tanA+tan²A
LHS = 2 + 2tan²A
LHS = 2(1+tan²A)
Here, we use formula (1+tan²A)=sec²A
LHS = 2sec²A=RHS
By : MANGESH K REPAL
Sir, there are multiple ways of solving a problem. I have also included your way of solving the problem. Thanks